X
This website uses 'cookies' in order to give you the best and most relevent information. Using this website, you acknowledge that you have read and understood our Privacy Policy. More info That's Fine
Jharkhand JSSC Excise Constable Vacancy 2022

Jharkhand JSSC Excise Constable Vacancy 2022

Name of Post: Jharkhand Excise Constable Online Form 2022
Post Date: 28/02/2022
Post Update Date: 28/02/2022
Short Information: Jharkhand Staff Selection Commission (JSSC) Are Invited For Recruitment of Excise Constable 2022. Interested Candidate Can Completed All Eligibility Criteria For Excise Constable Post And Apply Online. Before Apply Please Read Full Notification. Jharkhand Excise Constable Vacancy 2022.

Jharkhand Staff Selection Commission (JSSC)


झारखंड कर्मचारी चयन आयोग (JSSC)


JSSC Excise Constable Vacancy 2022


WWW.SARKARINAUKRIFIND.COM

IMPORTANT DATES APPLICATION FEE
  • Application Start: 25-Feb-2022
  • Last Date Apply Online: 26-Mar-2022
  • Last Date Pay Exam Fee : 29-Mar-2022
  • Complete Form Date : 01-Apr-2022
  • Admit Card : Available Soon
  • Exam Date : Available Soon
  • For Gen / OBC / EWS : Rs.100/-
  • For SC / ST : Rs.0/-
  • Pay Application Fee Through Online Debit Card, Credit Card, Net Banking Or Pay E-Challan Mode.
Age Limit
  • Minimum Age : 18 Years
  • Maximum Age : 25 Years
  • Age As on 01-Aug-2022.
  • Extra Age As Per Rules.
Vacancy Details
Total Vacancy: 583
Post Name Category Total Eligibility
Excise Constable Gen 237
  • 10th (High School) Exam Passed.
BC 32
EBC 50
EWS 59
SC 57
ST 148
Physical Standard
Gender Category Height Chest Running
Male Gen / OBC 160 CMS 81 CM 10 KM Run in 60 Minutes
SC / ST 155 CMS 79 CM
Female All 148 CMS NA 05 KM Run in 40 Minutes
IF You Satisfied By www.sarkarinaukrifind.com Please Like & Share with More People.
IMPORTANT LINKS
Apply Online Click Here
Download Notification Click Here
Official Website Click Here
For any Query and Feedback Contact us – info@sarkarinaukrifind.com

JSSC Vacancy 2022

Leave a Reply

Your email address will not be published. Required fields are marked *

19 − 1 =